proof for 1=2

[chethiyakb]

Let a=b

therefore a*a=ab

a*a +a*a=a*a+ab

2a*a=a*a+ab

2a*a-2ab=a*a+ab-2ab

2a*a-2ab=a*a-ab

2(a*a-2ab)=1(a*a-ab)

when both sides are divided by (a*a-ab) :D




ps: we can't divide a number by zero. If we divide, the result is undefined (usually said the infinity)

[tdevinda]

:S

this is total nonsense. When you substitute a for b at even the first instance you end up with 0=0....

Looks like you're new to maths. Did you just start AL? Finish the pure maths and you'll turn purple every time you remember you posted something like this :D

LoL...

[nimaz]

wrong maths!!

[yasasrd]

:S

this is total nonsense. When you substitute a for b at even the first instance you end up with 0=0....

Looks like you're new to maths. Did you just start AL? Finish the pure maths and you'll turn purple every time you remember you posted something like this :D

LoL...


:yes: :yes: :yes: :yes: :yes: :yes:

[fahoo_em]

its totaly wrong.
a=b kiyala ehama ganna bay.

[chethiyakb]

:S

this is total nonsense. When you substitute a for b at even the first instance you end up with 0=0....

Looks like you're new to maths. Did you just start AL? Finish the pure maths and you'll turn purple every time you remember you posted something like this :D

LoL...

I posted this for newcomers to the mathematics field. If u were at my age you gonna take this serious for sure.

Anyway this is a joke ( not when my math teacher gave this!!)

[henderson]

Let a=b

therefore a*a=ab

a*a +a*a=a*a+ab

2a*a=a*a+ab

2a*a-2ab=a*a+ab-2ab

2a*a-2ab=a*a-ab

2(a*a-2ab)=1(a*a-ab)

when both sides are divided by (a*a-ab)

Now the issue is your math is perfectly correct until last line,
how can the (a * a - 2ab)/(a*a-ab) = 1

so that is not a proof or nowhere near

[nipunaplus]

Malideve DEVANSLA KOHOMATH WENAS THALE KOLLO>>>>>>BECAUSE I AM DEVANS..........I AM PROUD TO BE A DEVAN

[JKSSSS]

a*a, 2a neme a squared

[madurax86]

mokadda me? :0
a=b
therefore a*a=ab

a*a +a*a=a*a+ab

2a*a=a*a+ab

2a*a-2ab=a*a+ab-2ab

2a*a-2ab=a*a-ab

2(a*a-ab)=1(a*a-ab) ...ur proof should be lyk dis i think but as u assigned a=b; then a*a-ab=0 how da hell are u gonna divide by 0? its limit goes to infinty! u better learn math b4 posting dude

[sherlock]

paithgaras kenek wathda?

[alagakkonara]

Guys this is a common problem, where we can prove any number is equal to any number.

This is something we normally learn while doing A/L maths. And of course we use division by zero, so yeah no real meaning in the proof.

Everybody who did maths knows that. So this proof is for those who dont know it to have some funtime figuring it out.

Give him a break,

[magicman]

:S

this is total nonsense. When you substitute a for b at even the first instance you end up with 0=0....

Looks like you're new to maths. Did you just start AL? Finish the pure maths and you'll turn purple every time you remember you posted something like this :D

LoL...



:yes::yes::yes::yes::yes::yes::yes::yes::yes::yes: :nerd::nerd::D:D:D

[aragon]

Very poor attempt to prove it, that's completely nonsense. U better to start learning maths from it's beginning.