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sajithd
12-23-2007, 10:17 PM
kaure hari dannawada me equation eka solve karanne

25^x-5^(x+1)+4=0 :D

nimaz
12-23-2007, 10:55 PM
u want 2 find da value of x??..can be done...it will take sum time..i think

sw7x
12-23-2007, 11:39 PM
mama dannawa X=7 i

sajithd
12-24-2007, 12:07 AM
hey machan how did u solve it?

can you post the solution step by step

hipa
12-24-2007, 12:54 AM
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.

mastercpj
12-25-2007, 01:29 PM
machan oka awkalanaya karala goda dhanna baerida??

Thenura
12-25-2007, 01:30 PM
ayyo gemak na :P

ereshthush
12-25-2007, 01:38 PM
ko ithin ewapan balanna

nimaz
12-25-2007, 01:53 PM
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.

hari!!

Thanu
12-25-2007, 02:02 PM
hard one

hehe

hipa
12-27-2007, 04:19 AM
sorry new to elakiri did not know how look at old threads
avakalana koroth mokadawenne ? function ekaka avakalanaya karala 0 t set karama lebenne ekko (i) maximum wena point (ii) nettham minimum wena point (ii) netham "herenna gihilla ayeth kelin yana point" (y=x^3, x=0 de wage) misak function eka 0 wena point lebenne ne . eheinda eqution solve karanne giyama avakalaneya karanna epa

Nimshan
12-27-2007, 04:49 AM
mara amaruwakane damme....:no:

hipa
12-27-2007, 09:39 AM
ganan gnne epa. mathe sira gathiya adu karanne hari amarui

kasuwa1235
12-27-2007, 09:47 AM
no i dont no

nabil
12-27-2007, 09:48 AM
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.
ahh yes yes. i was about to say that :D

hipa
12-27-2007, 09:57 AM
who is the most romantic? math guy or medico
a math guy and a medico are walking along and see a very pretty girl coming.
medico saw the girl's lungs, kidney's, spinal cords etc. math guy saw the smooth surfaces, uparima laksha (maximum points), avama laksha (minimum points), smooth surfaces and other interesting points (avakalanya 0 wena sthana).
Who is the most romantic ?

lahiru7
12-27-2007, 09:58 AM
Me mokadha ^

Muzain
12-27-2007, 10:18 AM
Maths Fail......Bang Owa Ahala Apiwa Cha Karanda epa

sajithd
12-27-2007, 10:35 PM
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.


thanx machan.