Quote:
Originally Posted by mag123
Originally Posted by WhiteWalker
ඔතන කල්ල තියෙන්නෙ සමීකරණ දෙක්ක අරං දෙකේම LHS < RHS නිසා RHS1 = RHS2 කියල අරං එහෙම ගන්න බෑ
5<10
5< 7 වුනා කියල 7 = 10 වෙන්නෑ
From (1) c^n/2<a^n/2+b^n/2
From(2) c^n/2<(a+b)^n/2
Soa^n/2+b^n/2=(a+b)^n/2
Ok from your equations ; that is (2) comes from (1),
Just put c=2 , a=3 and b=4 , n=4
then,
(1) > 4 < 9+16
(2) > 4< (3+4)^2 =49
So according to you SO LEFT SIDE IS EQUAL , RIGHT SIDE SHOULD BE EQUAL.
so 9+16 = 49 ???

YOU HAVE FORGOTTEN THE RIGHT ANGLE TRIANGLE. YOU CAN NOT FIX VALUES FOR,a,b,c,n AS YOU WANT.FOR EXAMPLETHIS VALUES MATCH FOR A RIGHT ANGLE TRIANGLEa=3,b=4,c=5,n=2now check