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05-16-2018, 10:53 PM

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Originally Posted by dilduda View Post
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05-16-2018, 11:05 PM

∫2xdx = x^2+c

13
∫2xdx = (13^2+c)-(10^2+C)
12
= 169-100
= 69


LOL

Last edited by charithtg; 05-16-2018 at 11:06 PM.
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05-16-2018, 11:20 PM

Quote:
Originally Posted by charithtg View Post
∫2xdx = x^2+c

13
∫2xdx = (13^2+c)-(10^2+C)
12
= 169-100
= 69


LOL
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05-16-2018, 11:38 PM

ගාන වැරදිලා බැ කිව්වොත්
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05-17-2018, 08:50 AM

bp
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05-17-2018, 01:53 PM

kohomada 69 uththare aawe?
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05-17-2018, 02:04 PM

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05-17-2018, 03:36 PM

Quote:
Originally Posted by charithtg View Post
∫2xdx = x^2+c

13
∫2xdx = (13^2+c)-(10^2+C)
12
= 169-100
= 69


LOL
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charithtg's Avatar
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05-17-2018, 09:41 PM

Quote:
Originally Posted by dilan silva View Post
kohomada 69 uththare aawe?
menna


Quote:
Originally Posted by charithtg View Post
∫2xdx = x^2+c

13
∫2xdx = (13^2+c)-(10^2+C)
12
= 169-100
= 69


LOL
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05-17-2018, 09:45 PM

Quote:
Originally Posted by charithtg View Post
∫2xdx = x^2+c

13
∫2xdx = (13^2+c)-(10^2+C)
12
= 169-100
= 69


LOL
monada bn me?
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